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Kaplan MCAT General Chem - Concept Check 6.1

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Hey guys, I had a question about a problem in Chapter 6 of the General Chem Kaplan book, concept check 6.1, question #1.

Given:
Q = 5.0 x 10^-2
Keq = 5.0 x 10^-3

The question then asks what the sign of the free energy change (delta G) would be.



My logic was that since the Q > Keq, the reaction will proceed to the left to reform more reactants in order to reach equilibrium. The answer key says the delta G of the reaction would be positive. But I am confused, because I thought that if...

Kaplan MCAT General Chem - Concept Check 6.1

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