I understand to identify a competitive inhibitor, the Km increases and the Vmax doesn't change.
I was going through a SB C/P problem (#77) and thought how could Km change based on a constant Vmax?
If Km=1/2Vmax, how does Km decrease/increase while Vmax stays the same?
According to the equation, wouldn't we always expect that with an increase in Vmax, there would be an increase in Km
Probably overthinking again.![:yawn:]( "Yawn :yawn:")
I was going through a SB C/P problem (#77) and thought how could Km change based on a constant Vmax?
If Km=1/2Vmax, how does Km decrease/increase while Vmax stays the same?
According to the equation, wouldn't we always expect that with an increase in Vmax, there would be an increase in Km
Probably overthinking again.
