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EK 1001 Physics Question #312

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Hey there!

Was going through a couple of EK 1001 Physics questions and came across this question that I couldn't quite figure out so hopefully someone here could lend some much needed clarification.

Here's a picture of the diagram and the question prompt: View attachment 207351

My attempt at a solution:
a. Torque (CW) = Torque (CCW) --> 0.2mg = 0.2f where m = mass of the sign; I picked the rotation point to be at the attachment point of the rope to the sign which is 0.2m away...

EK 1001 Physics Question #312

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