Why does Cd lose two electrons from its 5s orbital before losing any electrons from its 4d orbital? I thought the order of removal of electrons was the reverse order in which they were filled...therefore I would think that since 4d was filled after 5s, 4d electrons would be taken first.
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Is it just more favorable because a partially filled d orbital would be less stable...
Cd 2+
![[IMG]](http://math-science-resources.com/wp-content/uploads/2015/09/electron_orbital_filling_chart1308104179633.jpg)
Is it just more favorable because a partially filled d orbital would be less stable...
Cd 2+