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TPR Equilibrium question

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Ten moles of a compound were added to make a liter of solution, and the resulting pH was 5.7. What is the relationship between the Ka for the protonated form of the compound and Kb for the deprotonated form?

A. Ka < Kb
B. Ka = Kb
C. Ka > Kb
D. Cannot be determined

Can somebody please explain why the answer is A? I thought that if pH < 7, it is more acidic than basic and thus Ka > Kb.

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