"20. If a 10.0 g heating coil goes from 20 degrees C to 40 degrees C in 3.00 seconds, then what was the average power supply during this time if Ccoil = 3.00 J/g*K"
A. 0.20 W
B. 20 W
C. 200 W
D. 1800 W
I know that P = W/t and that the units are Watts = J/s but TBR says the answer is 200 W. To me, it looks like they never converted g to kg .... and Joule = kg*s^2/m^2
the math is Q = mcdeltaT which equals work and you just divide that by time to get power. When I do the math I get...
Joule Units? TBR phyics Ch.3
A. 0.20 W
B. 20 W
C. 200 W
D. 1800 W
I know that P = W/t and that the units are Watts = J/s but TBR says the answer is 200 W. To me, it looks like they never converted g to kg .... and Joule = kg*s^2/m^2
the math is Q = mcdeltaT which equals work and you just divide that by time to get power. When I do the math I get...
Joule Units? TBR phyics Ch.3