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Vmax and absolute activity

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Hi! The following is a question from C/P (#55) from EK FL 1. You don't need any info from the passage to answer this question, so I'm just posting the question below:
During one experiment, a fixed amount of D-trehalose (substrate) was added and the activity was 60% of its maximum, an absolute value of 35 nmol/min. The trypsin (enzyme) concentration was then doubled while the concentration of D-trehalose was held constant. How did the activity of the trypsin change during this time?

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Vmax and absolute activity

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