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AAMC Scored C/P #53

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So Zn +2HCl-> ZnCl2 + H2 + Cl2
Zn is (0 to 2+)->>>oxidized
H is (1+ to 0)->>>reduced

2Al + 6HCl-> 2AlCl3 + 3H2
Al is (0 to 3+)->>> oxidized
H is (1+ to 0)->>> reduced

I don't know what I was thinking when I chose C because Cl doesn't change it's oxidation state. (I think I some how formed Cl2)<<--dumb

I think I would have gotten it correct through POE, but I don't understand why the key says a new solid is formed when Al is mixed with Zn2+ (It did not say Zn...

AAMC Scored C/P #53

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